C51H57ClN4O2
1 compound has this formula on CompoundList.
- Molar mass
- 793.49g/mol
- Monoisotopic mass
- 792.4170Da
- Atoms
- 115
- Elements
- 5
- Rings plus double bonds
- 25
The formula C51H57ClN4O2 describes a molecule made of 51 carbon atoms, 57 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 5177.20%12.011 × 51 = 612.561 g/mol
- H Hydrogen × 577.24%1.008 × 57 = 57.456 g/mol
- Cl Chlorine × 14.47%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 47.06%14.007 × 4 = 56.028 g/mol
- O Oxygen × 24.03%15.999 × 2 = 31.998 g/mol
Compounds with the formula C51H57ClN4O2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C51H57ClN4O2?
The molar mass of C51H57ClN4O2 is 793.49 g/mol, calculated from standard atomic weights for 51 carbon atoms, 57 hydrogen atoms, 1 chlorine atom, 4 nitrogen atoms and 2 oxygen atoms. The monoisotopic mass is 792.4170 Da.
How many compounds have the formula C51H57ClN4O2?
CompoundList lists 1 compound with the molecular formula C51H57ClN4O2, including Orb3136638. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C51H57ClN4O2?
C51H57ClN4O2 has a degree of unsaturation of 25. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.