B2BaO4
1 compound has this formula on CompoundList.
- Molar mass
- 222.95g/mol
- Monoisotopic mass
- 223.9035Da
- Atoms
- 7
- Elements
- 3
The formula B2BaO4 describes a molecule made of 2 boron atoms, 1 barium atom and 4 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 29.70%10.81 × 2 = 21.620 g/mol
- Ba Barium × 161.60%137.33 × 1 = 137.330 g/mol
- O Oxygen × 428.70%15.999 × 4 = 63.996 g/mol
Compounds with the formula B2BaO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of B2BaO4?
The molar mass of B2BaO4 is 222.95 g/mol, calculated from standard atomic weights for 2 boron atoms, 1 barium atom and 4 oxygen atoms. The monoisotopic mass is 223.9035 Da.
How many compounds have the formula B2BaO4?
CompoundList lists 1 compound with the molecular formula B2BaO4, including Barium metaborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.