B3H12Na3O12
We do not list any compound with this exact formula yet.
- Molar mass
- 305.48g/mol
- Atoms
- 30
- Elements
- 4
The formula B3H12Na3O12 describes a molecule made of 3 boron atoms, 12 hydrogen atoms, 3 sodium atoms and 12 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 310.62%10.81 × 3 = 32.430 g/mol
- H Hydrogen × 123.96%1.008 × 12 = 12.096 g/mol
- Na Sodium × 322.58%22.99 × 3 = 68.970 g/mol
- O Oxygen × 1262.85%15.999 × 12 = 191.988 g/mol
Compounds with the formula B3H12Na3O12
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of B3H12Na3O12?
The molar mass of B3H12Na3O12 is 305.48 g/mol, calculated from standard atomic weights for 3 boron atoms, 12 hydrogen atoms, 3 sodium atoms and 12 oxygen atoms.