Molecular formula

B₄Na₂O₇

1 compound has this formula on CompoundList.

Molar mass: 201.21g/mol
Monoisotopic mass: 201.9812Da
Atoms: 13
Elements: 3

The formula B4Na2O7 describes a molecule made of 4 boron atoms, 2 sodium atoms and 7 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

B Boron × 421.49%
10.81 × 4 = 43.240 g/mol
Na Sodium × 222.85%
22.99 × 2 = 45.980 g/mol
O Oxygen × 755.66%
15.999 × 7 = 111.993 g/mol

Look up another formula

Compounds with the formula B4Na2O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Sodium tetraborate

CAS 1330-43-4B₄Na₂O₇

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What is the molar mass of B4Na2O7?

The molar mass of B4Na2O7 is 201.21 g/mol, calculated from standard atomic weights for 4 boron atoms, 2 sodium atoms and 7 oxygen atoms. The monoisotopic mass is 201.9812 Da.

How many compounds have the formula B4Na2O7?

CompoundList lists 1 compound with the molecular formula B4Na2O7, including Sodium tetraborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.