BaNaNbO4
1 compound has this formula on CompoundList.
- Molar mass
- 317.22g/mol
- Monoisotopic mass
- 317.7811Da
- Atoms
- 7
- Elements
- 4
The formula BaNaNbO4 describes a molecule made of 1 barium atom, 1 sodium atom, 1 niobium atom and 4 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Ba Barium × 143.29%137.33 × 1 = 137.330 g/mol
- Na Sodium × 17.25%22.99 × 1 = 22.990 g/mol
- Nb Niobium × 129.29%92.906 × 1 = 92.906 g/mol
- O Oxygen × 420.17%15.999 × 4 = 63.996 g/mol
Compounds with the formula BaNaNbO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of BaNaNbO4?
The molar mass of BaNaNbO4 is 317.22 g/mol, calculated from standard atomic weights for 1 barium atom, 1 sodium atom, 1 niobium atom and 4 oxygen atoms. The monoisotopic mass is 317.7811 Da.
How many compounds have the formula BaNaNbO4?
CompoundList lists 1 compound with the molecular formula BaNaNbO4, including Barium niobium sodium oxide (Ba2Nb5NaO15). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.