C10H13ClFNO3
19 compounds have this formula on CompoundList.
- Molar mass
- 249.67g/mol
- Monoisotopic mass
- 249.0568Da
- Atoms
- 29
- Elements
- 6
- Rings plus double bonds
- 4
The formula C10H13ClFNO3 describes a molecule made of 10 carbon atoms, 13 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1048.11%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 135.25%1.008 × 13 = 13.104 g/mol
- Cl Chlorine × 114.20%35.45 × 1 = 35.450 g/mol
- F Fluorine × 17.61%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 15.61%14.007 × 1 = 14.007 g/mol
- O Oxygen × 319.22%15.999 × 3 = 47.997 g/mol
Compounds with the formula C10H13ClFNO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 19 of 19 compounds
![2-Amino-3-fluoro-2-[(4-hydroxyphenyl)methyl]propanoic acid hydrochloride chemical structure, C10H13ClFNO3, CAS 73800-78-9](/s/WNPGDRMLWLQSDM-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C10H13ClFNO3?
The molar mass of C10H13ClFNO3 is 249.67 g/mol, calculated from standard atomic weights for 10 carbon atoms, 13 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 249.0568 Da.
How many compounds have the formula C10H13ClFNO3?
CompoundList lists 19 compounds with the molecular formula C10H13ClFNO3, including Methyl 3-amino-2-(4-fluorophenoxy)propanoate hydrochloride, Methyl 2-amino-3-(3-fluoro-4-hydroxyphenyl)propanoate hydrochloride, Methyl (S)-2-amino-3-(3-fluoro-4-hydroxyphenyl)propanoate hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C10H13ClFNO3?
C10H13ClFNO3 has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.