C10H16BF4N
3 compounds have this formula on CompoundList.
- Molar mass
- 237.05g/mol
- Monoisotopic mass
- 237.1312Da
- Atoms
- 32
- Elements
- 5
The formula C10H16BF4N describes a molecule made of 10 carbon atoms, 16 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1050.67%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 166.80%1.008 × 16 = 16.128 g/mol
- B Boron × 14.56%10.81 × 1 = 10.810 g/mol
- F Fluorine × 432.06%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 15.91%14.007 × 1 = 14.007 g/mol
Compounds with the formula C10H16BF4N
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C10H16BF4N?
The molar mass of C10H16BF4N is 237.05 g/mol, calculated from standard atomic weights for 10 carbon atoms, 16 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 nitrogen atom. The monoisotopic mass is 237.1312 Da.
How many compounds have the formula C10H16BF4N?
CompoundList lists 3 compounds with the molecular formula C10H16BF4N, including 1-Butyl-4-methylpyridinium tetrafluoroborate, 1-Butyl-3-methylpyridinium tetrafluoroborate, 1-Butyl-2-methylpyridinium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.