C10H4Cl3NO3
4 compounds have this formula on CompoundList.
- Molar mass
- 292.50g/mol
- Monoisotopic mass
- 290.9257Da
- Atoms
- 21
- Elements
- 5
- Rings plus double bonds
- 8
The formula C10H4Cl3NO3 describes a molecule made of 10 carbon atoms, 4 hydrogen atoms, 3 chlorine atoms, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1041.06%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 41.38%1.008 × 4 = 4.032 g/mol
- Cl Chlorine × 336.36%35.45 × 3 = 106.350 g/mol
- N Nitrogen × 14.79%14.007 × 1 = 14.007 g/mol
- O Oxygen × 316.41%15.999 × 3 = 47.997 g/mol
Compounds with the formula C10H4Cl3NO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
Frequently asked questions
What is the molar mass of C10H4Cl3NO3?
The molar mass of C10H4Cl3NO3 is 292.50 g/mol, calculated from standard atomic weights for 10 carbon atoms, 4 hydrogen atoms, 3 chlorine atoms, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 290.9257 Da.
How many compounds have the formula C10H4Cl3NO3?
CompoundList lists 4 compounds with the molecular formula C10H4Cl3NO3, including 4-Chloro-5-(2,4-dichlorophenyl)-1,2-oxazole-3-carboxylic acid, 5,6,8-Trichloro-1,4-dihydro-4-oxo-3-quinolinecarboxylic acid, 5,6,7-Trichloro-4-oxo-1,4-dihydroquinoline-2-carboxylic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C10H4Cl3NO3?
C10H4Cl3NO3 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.