CompoundList
Molecular formula

C10H4F6N4S

1 compound has this formula on CompoundList.

Molar mass
326.22g/mol
Monoisotopic mass
326.0061Da
Atoms
25
Elements
5
Rings plus double bonds
8

The formula C10H4F6N4S describes a molecule made of 10 carbon atoms, 4 hydrogen atoms, 6 fluorine atoms, 4 nitrogen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1036.82%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 41.24%
    1.008 × 4 = 4.032 g/mol
  • F Fluorine × 634.94%
    18.998 × 6 = 113.988 g/mol
  • N Nitrogen × 417.18%
    14.007 × 4 = 56.028 g/mol
  • S Sulfur × 19.83%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C10H4F6N4S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C10H4F6N4S?

The molar mass of C10H4F6N4S is 326.22 g/mol, calculated from standard atomic weights for 10 carbon atoms, 4 hydrogen atoms, 6 fluorine atoms, 4 nitrogen atoms and 1 sulfur atom. The monoisotopic mass is 326.0061 Da.

How many compounds have the formula C10H4F6N4S?

CompoundList lists 1 compound with the molecular formula C10H4F6N4S, including 5,7-Bis(trifluoromethyl)-3-cyano-2-(methylthio)pyrazolo[1,5-a]pyrimidine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H4F6N4S?

C10H4F6N4S has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.