C10H5ClFNO3
41 compounds have this formula on CompoundList.
- Molar mass
- 241.60g/mol
- Monoisotopic mass
- 240.9942Da
- Atoms
- 21
- Elements
- 6
- Rings plus double bonds
- 8
The formula C10H5ClFNO3 describes a molecule made of 10 carbon atoms, 5 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1049.71%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 52.09%1.008 × 5 = 5.040 g/mol
- Cl Chlorine × 114.67%35.45 × 1 = 35.450 g/mol
- F Fluorine × 17.86%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 15.80%14.007 × 1 = 14.007 g/mol
- O Oxygen × 319.87%15.999 × 3 = 47.997 g/mol
Compounds with the formula C10H5ClFNO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 41 of 41 compounds
- 8-Chloro-5-fluoro-4-hydroxyquinoline-3-carboxylic acid1065093-58-4C10H5ClFNO3
- 8-Chloro-7-fluoro-4-hydroxyquinoline-3-carboxylic acid1065093-59-5C10H5ClFNO3
- 7-Chloro-8-fluoro-1,4-dihydro-4-oxo-2-quinolinecarboxylic acid1340337-17-8C10H5ClFNO3
- 5-(5-Chloro-2-fluorophenyl)-1,2-oxazole-4-carboxylic acid1368438-25-8C10H5ClFNO3
- 3-(2-Chloro-4-fluorophenyl)-1,2-oxazole-5-carboxylic acid1126636-71-2C10H5ClFNO3
- 3-(3-Chloro-5-fluorophenyl)-1,2-oxazole-5-carboxylic acid1603434-38-3C10H5ClFNO3
- 3-(5-Chloro-2-fluorophenyl)-1,2-oxazole-5-carboxylic acid1595993-44-4C10H5ClFNO3
- 3-(4-Chloro-2-fluorophenyl)-1,2-oxazole-5-carboxylic acid1602954-52-8C10H5ClFNO3
- 3-(2-Chloro-5-fluorophenyl)-1,2-oxazole-5-carboxylic acid1889779-54-7C10H5ClFNO3
- 5-(3-Chloro-2-fluorophenyl)-1,2-oxazole-3-carboxylic acid1891723-02-6C10H5ClFNO3
- 5-(3-Chloro-5-fluorophenyl)-1,2-oxazole-3-carboxylic acid1892008-31-9C10H5ClFNO3
- 5-Chloro-6-fluoro-2-formyl-1H-indole-3-carboxylic acid2172482-50-5C10H5ClFNO3
- 5-(3-Chloro-2-fluorophenyl)-1,2-oxazole-4-carboxylic acid2229394-27-6C10H5ClFNO3
- 5-(2-Chloro-5-fluorophenyl)-1,2-oxazole-4-carboxylic acid2229196-43-2C10H5ClFNO3
- 5-(2-Chloro-6-fluorophenyl)-1,2-oxazole-4-carboxylic acid1878617-34-5C10H5ClFNO3
- 5-(3-Chloro-5-fluorophenyl)-1,2-oxazole-4-carboxylic acid2228876-13-7C10H5ClFNO3
- 5-(4-Chloro-2-fluorophenyl)-1,2-oxazole-4-carboxylic acid2229321-74-6C10H5ClFNO3
Frequently asked questions
What is the molar mass of C10H5ClFNO3?
The molar mass of C10H5ClFNO3 is 241.60 g/mol, calculated from standard atomic weights for 10 carbon atoms, 5 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 240.9942 Da.
How many compounds have the formula C10H5ClFNO3?
CompoundList lists 41 compounds with the molecular formula C10H5ClFNO3, including 5-(2-Chloro-4-fluorophenyl)-1,2-oxazole-4-carboxylic acid, 7-Chloro-6-fluoro-4-oxo-1,4-dihydroquinoline-3-carboxylic acid, 7-Chloro-8-fluoro-4-hydroxyquinoline-3-carboxylic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C10H5ClFNO3?
C10H5ClFNO3 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.