C10H9BF3KO3
2 compounds have this formula on CompoundList.
- Molar mass
- 284.08g/mol
- Monoisotopic mass
- 284.0234Da
- Atoms
- 27
- Elements
- 6
The formula C10H9BF3KO3 describes a molecule made of 10 carbon atoms, 9 hydrogen atoms, 1 boron atom, 3 fluorine atoms, 1 potassium atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1042.28%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 93.19%1.008 × 9 = 9.072 g/mol
- B Boron × 13.81%10.81 × 1 = 10.810 g/mol
- F Fluorine × 320.06%18.998 × 3 = 56.994 g/mol
- K Potassium × 113.76%39.098 × 1 = 39.098 g/mol
- O Oxygen × 316.90%15.999 × 3 = 47.997 g/mol
Compounds with the formula C10H9BF3KO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C10H9BF3KO3?
The molar mass of C10H9BF3KO3 is 284.08 g/mol, calculated from standard atomic weights for 10 carbon atoms, 9 hydrogen atoms, 1 boron atom, 3 fluorine atoms, 1 potassium atom and 3 oxygen atoms. The monoisotopic mass is 284.0234 Da.
How many compounds have the formula C10H9BF3KO3?
CompoundList lists 2 compounds with the molecular formula C10H9BF3KO3, including Potassium (3-ethoxycarbonylbenzoyl)-trifluoroboranuide, Potassium (4-ethoxycarbonylbenzoyl)-trifluoroboranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.