C10H9N5O3
42 compounds have this formula on CompoundList.
- Molar mass
- 247.21g/mol
- Monoisotopic mass
- 247.0705Da
- Atoms
- 27
- Elements
- 4
- Rings plus double bonds
- 9
The formula C10H9N5O3 describes a molecule made of 10 carbon atoms, 9 hydrogen atoms, 5 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1048.59%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 93.67%1.008 × 9 = 9.072 g/mol
- N Nitrogen × 528.33%14.007 × 5 = 70.035 g/mol
- O Oxygen × 319.42%15.999 × 3 = 47.997 g/mol
Compounds with the formula C10H9N5O3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 42 of 42 compounds
- N-(2-Amino-4,6-dihydroxypyrimidin-5-yl)nicotinamide1245317-49-0C10H9N5O3
- 5-Methyl-4-[(E)-(2-nitrophenyl)diazenyl]-2,4-dihydro-3H-pyrazol-3-one67036-87-7C10H9N5O3
- 3-[(4-Nitrophenyl)methyl]-1H-1,2,4-triazole-5-carboxamide63970-81-0C10H9N5O3
- Tetrazolo[1,5-a]quinazolin-5(1H)-one, 7,8-dimethoxy-62484-01-9C10H9N5O3
- 2-({[Cyano(hydrazinecarbonyl)methylidene]amino}amino)benzoic acid887574-63-2C10H9N5O3
- 5-Methyl-4-[(E)-(4-nitrophenyl)diazenyl]-2,4-dihydro-3H-pyrazol-3-one90844-48-7C10H9N5O3
- 4,4-Dimethyl-8-nitro-4H-benzo[b]tetrazolo[1,5-d][1,4]oxazine1235999-21-9C10H9N5O3
- 5-Methyl-4-nitro-N-(pyridin-2-yl)-1H-pyrazole-3-carboxamide115869-56-2C10H9N5O3
- 3-Amino-2-cyano-3-(3-nitroanilino)prop-2-enamide74914-56-0C10H9N5O3
- 5'-Oxo-2'-deoxy-8,5'-cycloadenosine869355-08-8C10H9N5O3
- 5-Acetamido-1-(pyrimidin-2-yl)-1H-pyrazole-4-carboxylic acid2680864-63-3C10H9N5O3
- 5-Acetamido-1-(pyridazin-3-yl)-1H-pyrazole-4-carboxylic acid2680860-65-3C10H9N5O3
- 3-(5-Acetamido-1H-1,2,3,4-tetrazol-1-yl)benzoic acid2680856-93-1C10H9N5O3
- 5-Acetamido-1-(pyrimidin-4-yl)-1H-pyrazole-4-carboxylic acid2680846-60-8C10H9N5O3
- 5-Acetamido-2-(1H-1,2,3,4-tetrazol-1-yl)benzoic acid2680713-75-9C10H9N5O3
- 3-[N-(1H-1,2,3,4-Tetrazol-5-yl)acetamido]benzoic acid2680739-71-1C10H9N5O3
- 2-(4-Acetamidophenyl)-2H-1,2,3,4-tetrazole-5-carboxylic acid2913411-78-4C10H9N5O3
- 4-((4-Carbamoyl-1H-1,2,3-triazol-5-yl)amino)benzoic acid74847-50-0C10H9N5O3
Frequently asked questions
What is the molar mass of C10H9N5O3?
The molar mass of C10H9N5O3 is 247.21 g/mol, calculated from standard atomic weights for 10 carbon atoms, 9 hydrogen atoms, 5 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 247.0705 Da.
How many compounds have the formula C10H9N5O3?
CompoundList lists 42 compounds with the molecular formula C10H9N5O3, including 4-Methyl-3-nitro-N-(1,2,4-triazol-4-yl)benzamide, 3-((1-Methyl-1H-pyrazol-5-yl)carbamoyl)pyrazine-2-carboxylic acid, 5-Amino-1-(2-nitrophenyl)-1H-pyrazole-4-carboxamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C10H9N5O3?
C10H9N5O3 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.