C119H154ClN21O40
1 compound has this formula on CompoundList.
- Molar mass
- 2554.10g/mol
- Monoisotopic mass
- 2552.0350Da
- Atoms
- 335
- Elements
- 5
- Rings plus double bonds
- 53
The formula C119H154ClN21O40 describes a molecule made of 119 carbon atoms, 154 hydrogen atoms, 1 chlorine atom, 21 nitrogen atoms and 40 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 11955.96%12.011 × 119 = 1429.309 g/mol
- H Hydrogen × 1546.08%1.008 × 154 = 155.232 g/mol
- Cl Chlorine × 11.39%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 2111.52%14.007 × 21 = 294.147 g/mol
- O Oxygen × 4025.06%15.999 × 40 = 639.960 g/mol
Compounds with the formula C119H154ClN21O40
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C119H154ClN21O40?
The molar mass of C119H154ClN21O40 is 2554.10 g/mol, calculated from standard atomic weights for 119 carbon atoms, 154 hydrogen atoms, 1 chlorine atom, 21 nitrogen atoms and 40 oxygen atoms. The monoisotopic mass is 2552.0350 Da.
How many compounds have the formula C119H154ClN21O40?
CompoundList lists 1 compound with the molecular formula C119H154ClN21O40, including Ramoplanin A2. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C119H154ClN21O40?
C119H154ClN21O40 has a degree of unsaturation of 53. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.