C123H198N16O40
1 compound has this formula on CompoundList.
- Molar mass
- 2541.01g/mol
- Monoisotopic mass
- 2539.3951Da
- Atoms
- 377
- Elements
- 4
- Rings plus double bonds
- 33
The formula C123H198N16O40 describes a molecule made of 123 carbon atoms, 198 hydrogen atoms, 16 nitrogen atoms and 40 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 12358.14%12.011 × 123 = 1477.353 g/mol
- H Hydrogen × 1987.85%1.008 × 198 = 199.584 g/mol
- N Nitrogen × 168.82%14.007 × 16 = 224.112 g/mol
- O Oxygen × 4025.19%15.999 × 40 = 639.960 g/mol
Compounds with the formula C123H198N16O40
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C123H198N16O40?
The molar mass of C123H198N16O40 is 2541.01 g/mol, calculated from standard atomic weights for 123 carbon atoms, 198 hydrogen atoms, 16 nitrogen atoms and 40 oxygen atoms. The monoisotopic mass is 2539.3951 Da.
How many compounds have the formula C123H198N16O40?
CompoundList lists 1 compound with the molecular formula C123H198N16O40, including 1-O-[2-(Benzylcarbamoylamino)propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-(diethylcarbamoylamino)propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-[diethylcarbamoyl(ethyl)amino]propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-(dimethylcarbamoylamino)propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-[dimethylcarbamoyl(methyl)amino]propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-[ethylcarbamoyl(methyl)amino]propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-[ethyl(ethylcarbamoyl)amino]propyl] 4-O-propan-2-yl but-2-enedioate, 1-O-[2-(phenylcarbamoylamino)propyl] 4-O-propan-2-yl but-2-enedioate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C123H198N16O40?
C123H198N16O40 has a degree of unsaturation of 33. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.