C128H239F3N26O24
1 compound has this formula on CompoundList.
- Molar mass
- 2583.47g/mol
- Monoisotopic mass
- 2581.8233Da
- Atoms
- 420
- Elements
- 5
- Rings plus double bonds
- 21
The formula C128H239F3N26O24 describes a molecule made of 128 carbon atoms, 239 hydrogen atoms, 3 fluorine atoms, 26 nitrogen atoms and 24 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 12859.51%12.011 × 128 = 1537.408 g/mol
- H Hydrogen × 2399.33%1.008 × 239 = 240.912 g/mol
- F Fluorine × 32.21%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 2614.10%14.007 × 26 = 364.182 g/mol
- O Oxygen × 2414.86%15.999 × 24 = 383.976 g/mol
Compounds with the formula C128H239F3N26O24
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C128H239F3N26O24?
The molar mass of C128H239F3N26O24 is 2583.47 g/mol, calculated from standard atomic weights for 128 carbon atoms, 239 hydrogen atoms, 3 fluorine atoms, 26 nitrogen atoms and 24 oxygen atoms. The monoisotopic mass is 2581.8233 Da.
How many compounds have the formula C128H239F3N26O24?
CompoundList lists 1 compound with the molecular formula C128H239F3N26O24, including Sinapultide TFA. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C128H239F3N26O24?
C128H239F3N26O24 has a degree of unsaturation of 21. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.