CompoundList
Molecular formula

C12H15Cl2FN4

2 compounds have this formula on CompoundList.

Molar mass
305.18g/mol
Monoisotopic mass
304.0658Da
Atoms
34
Elements
5
Rings plus double bonds
6

The formula C12H15Cl2FN4 describes a molecule made of 12 carbon atoms, 15 hydrogen atoms, 2 chlorine atoms, 1 fluorine atom and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1247.23%
    12.011 × 12 = 144.132 g/mol
  • H Hydrogen × 154.95%
    1.008 × 15 = 15.120 g/mol
  • Cl Chlorine × 223.23%
    35.45 × 2 = 70.900 g/mol
  • F Fluorine × 16.23%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 418.36%
    14.007 × 4 = 56.028 g/mol
Look up another formula

Compounds with the formula C12H15Cl2FN4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C12H15Cl2FN4?

The molar mass of C12H15Cl2FN4 is 305.18 g/mol, calculated from standard atomic weights for 12 carbon atoms, 15 hydrogen atoms, 2 chlorine atoms, 1 fluorine atom and 4 nitrogen atoms. The monoisotopic mass is 304.0658 Da.

How many compounds have the formula C12H15Cl2FN4?

CompoundList lists 2 compounds with the molecular formula C12H15Cl2FN4, including 3-(2-Fluorophenyl)-5H,6H,7H,8H-(1,2,4)triazolo(4,3-a)pyridin-6-amine dihydrochloride, 3-[(3-Fluorophenyl)methyl]-5H,6H,7H,8H-[1,2,4]triazolo[4,3-a]pyrazine dihydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C12H15Cl2FN4?

C12H15Cl2FN4 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.