CompoundList
Molecular formula

C12H18ClF2NO5

1 compound has this formula on CompoundList.

Molar mass
329.72g/mol
Monoisotopic mass
329.0842Da
Atoms
39
Elements
6
Rings plus double bonds
3

The formula C12H18ClF2NO5 describes a molecule made of 12 carbon atoms, 18 hydrogen atoms, 1 chlorine atom, 2 fluorine atoms, 1 nitrogen atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1243.71%
    12.011 × 12 = 144.132 g/mol
  • H Hydrogen × 185.50%
    1.008 × 18 = 18.144 g/mol
  • Cl Chlorine × 110.75%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 211.52%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 14.25%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 524.26%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C12H18ClF2NO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C12H18ClF2NO5?

The molar mass of C12H18ClF2NO5 is 329.72 g/mol, calculated from standard atomic weights for 12 carbon atoms, 18 hydrogen atoms, 1 chlorine atom, 2 fluorine atoms, 1 nitrogen atom and 5 oxygen atoms. The monoisotopic mass is 329.0842 Da.

How many compounds have the formula C12H18ClF2NO5?

CompoundList lists 1 compound with the molecular formula C12H18ClF2NO5, including 1-tert-Butyl 2-chloromethyl (2S,4R)-4-(difluoromethoxy)pyrrolidine-1,2-dicarboxylate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C12H18ClF2NO5?

C12H18ClF2NO5 has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.