C12H36B2F8N6OP2
1 compound has this formula on CompoundList.
- Molar mass
- 516.01g/mol
- Monoisotopic mass
- 516.2484Da
- Atoms
- 67
- Elements
- 7
The formula C12H36B2F8N6OP2 describes a molecule made of 12 carbon atoms, 36 hydrogen atoms, 2 boron atoms, 8 fluorine atoms, 6 nitrogen atoms, 1 oxygen atom and 2 phosphorus atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1227.93%12.011 × 12 = 144.132 g/mol
- H Hydrogen × 367.03%1.008 × 36 = 36.288 g/mol
- B Boron × 24.19%10.81 × 2 = 21.620 g/mol
- F Fluorine × 829.45%18.998 × 8 = 151.984 g/mol
- N Nitrogen × 616.29%14.007 × 6 = 84.042 g/mol
- O Oxygen × 13.10%15.999 × 1 = 15.999 g/mol
- P Phosphorus × 212.01%30.974 × 2 = 61.948 g/mol
Compounds with the formula C12H36B2F8N6OP2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![mu-Oxo-bis[tris(dimethylamino)phosphonium] Bis(tetrafluoroborate) chemical structure, C12H36B2F8N6OP2, CAS 55881-03-3](/s/MSSSPRSPUHPRKJ-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C12H36B2F8N6OP2?
The molar mass of C12H36B2F8N6OP2 is 516.01 g/mol, calculated from standard atomic weights for 12 carbon atoms, 36 hydrogen atoms, 2 boron atoms, 8 fluorine atoms, 6 nitrogen atoms, 1 oxygen atom and 2 phosphorus atoms. The monoisotopic mass is 516.2484 Da.
How many compounds have the formula C12H36B2F8N6OP2?
CompoundList lists 1 compound with the molecular formula C12H36B2F8N6OP2, including mu-Oxo-bis[tris(dimethylamino)phosphonium] Bis(tetrafluoroborate). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.