CompoundList
Molecular formula

C13H15N7O

12 compounds have this formula on CompoundList.

Molar mass
285.31g/mol
Monoisotopic mass
285.1338Da
Atoms
36
Elements
4
Rings plus double bonds
10

The formula C13H15N7O describes a molecule made of 13 carbon atoms, 15 hydrogen atoms, 7 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1354.73%
    12.011 × 13 = 156.143 g/mol
  • H Hydrogen × 155.30%
    1.008 × 15 = 15.120 g/mol
  • N Nitrogen × 734.37%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 15.61%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C13H15N7O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 12 of 12 compounds

Frequently asked questions

What is the molar mass of C13H15N7O?

The molar mass of C13H15N7O is 285.31 g/mol, calculated from standard atomic weights for 13 carbon atoms, 15 hydrogen atoms, 7 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 285.1338 Da.

How many compounds have the formula C13H15N7O?

CompoundList lists 12 compounds with the molecular formula C13H15N7O, including 2-(5-Aminotetrazol-2-yl)-N-[(Z)-[(E)-4-phenylbut-3-en-2-ylidene]amino]acetamide, 2-({7-[(4-Methylphenyl)amino]-3H-[1,2,3]triazolo[4,5-d]pyrimidin-5-yl}amino)ethan-1-ol, 7-(4-Methylpiperazin-1-yl)pyrido[3,4-e][1,2,4]triazolo[1,5-a]pyrimidin-6(7H)-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C13H15N7O?

C13H15N7O has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.