CompoundList
Molecular formula

C13H17F2N3O5S

1 compound has this formula on CompoundList.

Molar mass
365.35g/mol
Monoisotopic mass
365.0857Da
Atoms
41
Elements
6
Rings plus double bonds
6

The formula C13H17F2N3O5S describes a molecule made of 13 carbon atoms, 17 hydrogen atoms, 2 fluorine atoms, 3 nitrogen atoms, 5 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1342.74%
    12.011 × 13 = 156.143 g/mol
  • H Hydrogen × 174.69%
    1.008 × 17 = 17.136 g/mol
  • F Fluorine × 210.40%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 311.50%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 521.90%
    15.999 × 5 = 79.995 g/mol
  • S Sulfur × 18.78%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C13H17F2N3O5S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C13H17F2N3O5S?

The molar mass of C13H17F2N3O5S is 365.35 g/mol, calculated from standard atomic weights for 13 carbon atoms, 17 hydrogen atoms, 2 fluorine atoms, 3 nitrogen atoms, 5 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 365.0857 Da.

How many compounds have the formula C13H17F2N3O5S?

CompoundList lists 1 compound with the molecular formula C13H17F2N3O5S, including (2R,3R)-2-(2,4-Difluorophenyl)-1-(1H-1,2,4-triazol-1-yl)butane-2,3-diol methanesulfonate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C13H17F2N3O5S?

C13H17F2N3O5S has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.