C13H23ClS3
1 compound has this formula on CompoundList.
- Molar mass
- 310.96g/mol
- Monoisotopic mass
- 310.0650Da
- Atoms
- 40
- Elements
- 4
- Rings plus double bonds
- 2
The formula C13H23ClS3 describes a molecule made of 13 carbon atoms, 23 hydrogen atoms, 1 chlorine atom and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1350.21%12.011 × 13 = 156.143 g/mol
- H Hydrogen × 237.46%1.008 × 23 = 23.184 g/mol
- Cl Chlorine × 111.40%35.45 × 1 = 35.450 g/mol
- S Sulfur × 330.93%32.06 × 3 = 96.180 g/mol
Compounds with the formula C13H23ClS3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![Sulfonium, [5-(1,1-dimethylethyl)-4-(2,2-dimethylpropyl)-3H-1,2-dithiol-3-ylidene]methyl-, chloride (1:1) chemical structure, C13H23ClS3, CAS 68784-93-0](/s/PZAXPDVHHXBKOS-UHFFFAOYSA-M.svg)
Frequently asked questions
What is the molar mass of C13H23ClS3?
The molar mass of C13H23ClS3 is 310.96 g/mol, calculated from standard atomic weights for 13 carbon atoms, 23 hydrogen atoms, 1 chlorine atom and 3 sulfur atoms. The monoisotopic mass is 310.0650 Da.
How many compounds have the formula C13H23ClS3?
CompoundList lists 1 compound with the molecular formula C13H23ClS3, including Sulfonium, [5-(1,1-dimethylethyl)-4-(2,2-dimethylpropyl)-3H-1,2-dithiol-3-ylidene]methyl-, chloride (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C13H23ClS3?
C13H23ClS3 has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.