CompoundList
Molecular formula

C13H24O10

10 compounds have this formula on CompoundList.

Molar mass
340.33g/mol
Monoisotopic mass
340.1369Da
Atoms
47
Elements
3
Rings plus double bonds
2

The formula C13H24O10 describes a molecule made of 13 carbon atoms, 24 hydrogen atoms and 10 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1345.88%
    12.011 × 13 = 156.143 g/mol
  • H Hydrogen × 247.11%
    1.008 × 24 = 24.192 g/mol
  • O Oxygen × 1047.01%
    15.999 × 10 = 159.990 g/mol
Look up another formula

Compounds with the formula C13H24O10

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C13H24O10?

The molar mass of C13H24O10 is 340.33 g/mol, calculated from standard atomic weights for 13 carbon atoms, 24 hydrogen atoms and 10 oxygen atoms. The monoisotopic mass is 340.1369 Da.

How many compounds have the formula C13H24O10?

CompoundList lists 10 compounds with the molecular formula C13H24O10, including Methyl 2-O-alpha-rhamnopyranosyl-beta-galactopyranoside, Methyl 2-O-mannopyranosyl-rhamnopyranoside, Pseudo-cellobiose. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C13H24O10?

C13H24O10 has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.