CompoundList
Molecular formula

C14H11BO5

2 compounds have this formula on CompoundList.

Molar mass
270.05g/mol
Monoisotopic mass
270.0700Da
Atoms
31
Elements
4

The formula C14H11BO5 describes a molecule made of 14 carbon atoms, 11 hydrogen atoms, 1 boron atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1462.27%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 114.11%
    1.008 × 11 = 11.088 g/mol
  • B Boron × 14.00%
    10.81 × 1 = 10.810 g/mol
  • O Oxygen × 529.62%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C14H11BO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C14H11BO5?

The molar mass of C14H11BO5 is 270.05 g/mol, calculated from standard atomic weights for 14 carbon atoms, 11 hydrogen atoms, 1 boron atom and 5 oxygen atoms. The monoisotopic mass is 270.0700 Da.

How many compounds have the formula C14H11BO5?

CompoundList lists 2 compounds with the molecular formula C14H11BO5, including 4-((1-Hydroxy-1,3-dihydrobenzo[c][1,2]oxaborol-5-yl)oxy)benzoic acid, 4-(1-Hydroxy-1,3-dihydrobenzo[c][1,2]oxaborol-6-yloxy)benzoic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.