C14H14BBrO4
1 compound has this formula on CompoundList.
- Molar mass
- 336.98g/mol
- Monoisotopic mass
- 336.0169Da
- Atoms
- 34
- Elements
- 5
The formula C14H14BBrO4 describes a molecule made of 14 carbon atoms, 14 hydrogen atoms, 1 boron atom, 1 bromine atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1449.90%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 144.19%1.008 × 14 = 14.112 g/mol
- B Boron × 13.21%10.81 × 1 = 10.810 g/mol
- Br Bromine × 123.71%79.904 × 1 = 79.904 g/mol
- O Oxygen × 418.99%15.999 × 4 = 63.996 g/mol
Compounds with the formula C14H14BBrO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C14H14BBrO4?
The molar mass of C14H14BBrO4 is 336.98 g/mol, calculated from standard atomic weights for 14 carbon atoms, 14 hydrogen atoms, 1 boron atom, 1 bromine atom and 4 oxygen atoms. The monoisotopic mass is 336.0169 Da.
How many compounds have the formula C14H14BBrO4?
CompoundList lists 1 compound with the molecular formula C14H14BBrO4, including 3-Bromo-2-(3'-methoxybenzyloxy)phenylboronic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.