CompoundList
Molecular formula

C14H15N7O3

11 compounds have this formula on CompoundList.

Molar mass
329.32g/mol
Monoisotopic mass
329.1236Da
Atoms
39
Elements
4
Rings plus double bonds
11

The formula C14H15N7O3 describes a molecule made of 14 carbon atoms, 15 hydrogen atoms, 7 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1451.06%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 154.59%
    1.008 × 15 = 15.120 g/mol
  • N Nitrogen × 729.77%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 314.57%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C14H15N7O3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C14H15N7O3?

The molar mass of C14H15N7O3 is 329.32 g/mol, calculated from standard atomic weights for 14 carbon atoms, 15 hydrogen atoms, 7 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 329.1236 Da.

How many compounds have the formula C14H15N7O3?

CompoundList lists 11 compounds with the molecular formula C14H15N7O3, including Ethyl 1-(4-amino-1,2,5-oxadiazol-3-yl)-5-(anilinomethyl)-1H-1,2,3-triazole-4-carboxylate, 2-(4,4-Dimethyl-2,5-dioxoimidazolidin-1-yl)-N-[4-(tetrazol-1-yl)phenyl]acetamide, 2-(1,3-Dimethyl-2,6-dioxopurin-7-yl)-N-(4-methylpyrimidin-2-yl)acetamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H15N7O3?

C14H15N7O3 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.