C14H17BrO3
58 compounds have this formula on CompoundList.
- Molar mass
- 313.19g/mol
- Monoisotopic mass
- 312.0361Da
- Atoms
- 35
- Elements
- 4
- Rings plus double bonds
- 6
The formula C14H17BrO3 describes a molecule made of 14 carbon atoms, 17 hydrogen atoms, 1 bromine atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1453.69%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 175.47%1.008 × 17 = 17.136 g/mol
- Br Bromine × 125.51%79.904 × 1 = 79.904 g/mol
- O Oxygen × 315.33%15.999 × 3 = 47.997 g/mol
Compounds with the formula C14H17BrO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 58 of 58 compounds
- 4-(4-Bromophenyl)-4-(methoxymethoxy)cyclohexanone1523365-96-9C14H17BrO3
- tert-Butyl (2E)-3-(2-bromo-5-methoxyphenyl)prop-2-enoate2172630-12-3C14H17BrO3
- Ethyl 4-(3-bromophenyl)oxane-4-carboxylate179420-76-9C14H17BrO3
- Ethyl 4-(4-bromophenyl)tetrahydro-2H-pyran-4-carboxylate1227160-22-6C14H17BrO3
- Cyclopropylmethyl 2-(4-bromo-2,6-dimethylphenoxy)acetate817565-65-4C14H17BrO3
- 1-Penten-3-ol, 1-(2-bromo-4,5-methylenedioxyphenyl)-4,4-dimethyl-58344-97-1C14H17BrO3
- Benzaldehyde, 3-bromo-5-ethoxy-4-[(3-methyl-2-butenyl)oxy]-1153393-04-4C14H17BrO3
- (3-Bromo-4-cyclopropylmethoxy-phenyl)-acetic acid ethyl ester1445891-78-0C14H17BrO3
- (E)-4-Bromo-3-(2,3-dimethyl-phenoxy)-but-2-enoic acid ethyl ester1192000-28-4C14H17BrO3
- 8-(4-Bromophenoxy)-1,4-dioxaspiro[4.5]decane1312478-73-1C14H17BrO3
- 2-Bromo-5-(cyclohexylmethoxy)benzoic acid1519244-22-4C14H17BrO3
- Ethyl 1-((4-bromophenoxy)methyl)cyclobutanecarboxylate1504394-54-0C14H17BrO3
- 6-Bromo-2,2-dimethyl-4-methylene-2H-1-benzopyran-3,3(4H)-dimethanol1504391-68-7C14H17BrO3
- Methyl 5-bromo-4-cyclopropyl-2-isopropoxybenzoate1628750-22-0C14H17BrO3
- 2-(4-Bromophenyl)-2-oxoethyl hexanoate15441-45-9C14H17BrO3
- 2-[3-Bromo-4-(cyclopropylmethoxy)phenyl]-2-methyl-1,3-dioxolane1268511-88-1C14H17BrO3
- 8-(3-Bromophenyl)-1,4-dioxaspiro[4.5]decan-8-ol2002032-23-5C14H17BrO3
- 3-(6-Bromochroman-2-yl)propionic acid ethyl ester1958099-17-6C14H17BrO3
- Cyclohexyl 2-bromo-5-methoxybenzoate1992996-58-3C14H17BrO3
- tert-Butyl 4-(4-bromophenyl)-3-oxobutanoate1639411-31-6C14H17BrO3
- Propan-2-yl 4-(4-bromophenyl)-5-oxopentanoate1476776-40-5C14H17BrO3
- Propan-2-yl 3-[2-(4-bromophenyl)oxiran-2-yl]propanoate1476776-39-2C14H17BrO3
- tert-Butyl (2E)-3-(3-bromo-4-methoxyphenyl)prop-2-enoate1189128-27-5C14H17BrO3
- Ethyl 3-(5-bromo-2-propoxyphenyl)-2-propenoate1269592-30-4C14H17BrO3
- Methyl 3-bromo-5-(cyclopentylmethoxy)benzoate2704480-27-1C14H17BrO3
- 2-[2-(3-Bromophenyl)-2-oxoethyl]-4-methylpentanoic acid2137841-41-7C14H17BrO3
- 2-[2-(4-Bromophenyl)-2-oxoethyl]-4-methylpentanoic acid2138406-79-6C14H17BrO3
- tert-Butyl 4-(3-bromophenyl)-3-oxobutanoate3078343-39-9C14H17BrO3
- Ethyl 2-(2-bromo-3-formylbenzyl)-2-methylpropanoate1269411-33-7C14H17BrO3
- Methyl 6-bromo-3-(cyclobutylmethoxy)-2-methylbenzoate3078494-12-6C14H17BrO3
- tert-Butyl 4-(4-bromophenyl)-4-oxobutanoate1207195-68-3C14H17BrO3
- 3-(3-Bromo-4-propan-2-yloxyphenyl)pentane-2,4-dione220982-77-4C14H17BrO3
- 5-(5-Bromopent-1-yn-1-yl)-1,2,3-trimethoxybenzene1042073-75-5C14H17BrO3
- 8-(2-Bromophenyl)-1,4-dioxaspiro[4.5]decan-8-ol2889541-63-1C14H17BrO3
Frequently asked questions
What is the molar mass of C14H17BrO3?
The molar mass of C14H17BrO3 is 313.19 g/mol, calculated from standard atomic weights for 14 carbon atoms, 17 hydrogen atoms, 1 bromine atom and 3 oxygen atoms. The monoisotopic mass is 312.0361 Da.
How many compounds have the formula C14H17BrO3?
CompoundList lists 58 compounds with the molecular formula C14H17BrO3, including 2-Bromo-4-(cyclopentyloxy)-5-ethoxybenzaldehyde, 4-(2-Bromopropanoyl)phenyl 2,2-dimethylpropanoate, 2-Bromo-1-[3-(cyclopentyloxy)-4-methoxyphenyl]ethan-1-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H17BrO3?
C14H17BrO3 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.