CompoundList
Molecular formula

C14H17BrO5

11 compounds have this formula on CompoundList.

Molar mass
345.19g/mol
Monoisotopic mass
344.0259Da
Atoms
37
Elements
4
Rings plus double bonds
6

The formula C14H17BrO5 describes a molecule made of 14 carbon atoms, 17 hydrogen atoms, 1 bromine atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1448.71%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 174.96%
    1.008 × 17 = 17.136 g/mol
  • Br Bromine × 123.15%
    79.904 × 1 = 79.904 g/mol
  • O Oxygen × 523.17%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C14H17BrO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C14H17BrO5?

The molar mass of C14H17BrO5 is 345.19 g/mol, calculated from standard atomic weights for 14 carbon atoms, 17 hydrogen atoms, 1 bromine atom and 5 oxygen atoms. The monoisotopic mass is 344.0259 Da.

How many compounds have the formula C14H17BrO5?

CompoundList lists 11 compounds with the molecular formula C14H17BrO5, including tert-Butyl 2-(2-bromo-4-formyl-6-methoxyphenoxy)acetate, Isopropyl (5-bromo-2-ethoxy-4-formylphenoxy)acetate, Ethyl 2-(2-bromo-6-ethoxy-4-formylphenoxy)propanoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H17BrO5?

C14H17BrO5 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.