CompoundList
Sign in
Molecular formula

C14H19Cl3N4O3S2

1 compound has this formula on CompoundList.

Molar mass
461.80g/mol
Monoisotopic mass
459.9964Da
Atoms
45
Elements
6
Rings plus double bonds
6

The formula C14H19Cl3N4O3S2 describes a molecule made of 14 carbon atoms, 19 hydrogen atoms, 3 chlorine atoms, 4 nitrogen atoms, 3 oxygen atoms and 2 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1436.41%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 194.15%
    1.008 × 19 = 19.152 g/mol
  • Cl Chlorine × 323.03%
    35.45 × 3 = 106.350 g/mol
  • N Nitrogen × 412.13%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 310.39%
    15.999 × 3 = 47.997 g/mol
  • S Sulfur × 213.88%
    32.06 × 2 = 64.120 g/mol
Look up another formula

Compounds with the formula C14H19Cl3N4O3S2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

2,2-Dimethyl-N-[2,2,2-trichloro-1-[(4-sulfamoylphenyl)carbamothioylamino]ethyl]propanamide chemical structure, C14H19Cl3N4O3S2, CAS 321686-55-9
2,2-Dimethyl-N-[2,2,2-trichloro-1-[(4-sulfamoylphenyl)carbamothioylamino]ethyl]propanamide
CAS 321686-55-9C14H19Cl3N4O3S2

Frequently asked questions

What is the molar mass of C14H19Cl3N4O3S2?

The molar mass of C14H19Cl3N4O3S2 is 461.80 g/mol, calculated from standard atomic weights for 14 carbon atoms, 19 hydrogen atoms, 3 chlorine atoms, 4 nitrogen atoms, 3 oxygen atoms and 2 sulfur atoms. The monoisotopic mass is 459.9964 Da.

How many compounds have the formula C14H19Cl3N4O3S2?

CompoundList lists 1 compound with the molecular formula C14H19Cl3N4O3S2, including 2,2-Dimethyl-N-[2,2,2-trichloro-1-[(4-sulfamoylphenyl)carbamothioylamino]ethyl]propanamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H19Cl3N4O3S2?

C14H19Cl3N4O3S2 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.