C14H19ClO3S
4 compounds have this formula on CompoundList.
- Molar mass
- 302.81g/mol
- Monoisotopic mass
- 302.0743Da
- Atoms
- 38
- Elements
- 5
- Rings plus double bonds
- 5
The formula C14H19ClO3S describes a molecule made of 14 carbon atoms, 19 hydrogen atoms, 1 chlorine atom, 3 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1455.53%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 196.32%1.008 × 19 = 19.152 g/mol
- Cl Chlorine × 111.71%35.45 × 1 = 35.450 g/mol
- O Oxygen × 315.85%15.999 × 3 = 47.997 g/mol
- S Sulfur × 110.59%32.06 × 1 = 32.060 g/mol
Compounds with the formula C14H19ClO3S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
![3-[1-(Benzyloxy)-3-chloropropan-2-yl]-1lambda6-thiolane-1,1-dione chemical structure, C14H19ClO3S, CAS 1876924-63-8](/s/XBHOLKPLPIYSFB-UHFFFAOYSA-N.svg)
![1-[3-(Benzyloxy)-2-methylpropyl]cyclopropane-1-sulfonyl chloride chemical structure, C14H19ClO3S, CAS 2138075-32-6](/s/WXHVUIRTLQXYKI-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C14H19ClO3S?
The molar mass of C14H19ClO3S is 302.81 g/mol, calculated from standard atomic weights for 14 carbon atoms, 19 hydrogen atoms, 1 chlorine atom, 3 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 302.0743 Da.
How many compounds have the formula C14H19ClO3S?
CompoundList lists 4 compounds with the molecular formula C14H19ClO3S, including 2,2,5,7,8-Pentamethyl-chromane-6-sulfonyl chloride, (1-((Benzyloxy)methyl)cyclopentyl)methanesulfonyl chloride, 3-[1-(Benzyloxy)-3-chloropropan-2-yl]-1lambda6-thiolane-1,1-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H19ClO3S?
C14H19ClO3S has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.