CompoundList
Molecular formula

C14H23Br2N

5 compounds have this formula on CompoundList.

Molar mass
365.15g/mol
Monoisotopic mass
363.0197Da
Atoms
40
Elements
4
Rings plus double bonds
3

The formula C14H23Br2N describes a molecule made of 14 carbon atoms, 23 hydrogen atoms, 2 bromine atoms and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1446.05%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 236.35%
    1.008 × 23 = 23.184 g/mol
  • Br Bromine × 243.76%
    79.904 × 2 = 159.808 g/mol
  • N Nitrogen × 13.84%
    14.007 × 1 = 14.007 g/mol
Look up another formula

Compounds with the formula C14H23Br2N

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 5 of 5 compounds

Frequently asked questions

What is the molar mass of C14H23Br2N?

The molar mass of C14H23Br2N is 365.15 g/mol, calculated from standard atomic weights for 14 carbon atoms, 23 hydrogen atoms, 2 bromine atoms and 1 nitrogen atom. The monoisotopic mass is 363.0197 Da.

How many compounds have the formula C14H23Br2N?

CompoundList lists 5 compounds with the molecular formula C14H23Br2N, including Benzyl(4-bromobutyl)(propan-2-yl)amine hydrobromide, 1-(3-Bromo-1-adamantyl)pyrrolidine hydrobromide, N-(2-Bromo-2-phenylethyl)-N-propylpropan-1-amine--hydrogen bromide (1/1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H23Br2N?

C14H23Br2N has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.