CompoundList
Molecular formula

C14H9F4N3

10 compounds have this formula on CompoundList.

Molar mass
295.24g/mol
Monoisotopic mass
295.0733Da
Atoms
30
Elements
4
Rings plus double bonds
10

The formula C14H9F4N3 describes a molecule made of 14 carbon atoms, 9 hydrogen atoms, 4 fluorine atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1456.96%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 93.07%
    1.008 × 9 = 9.072 g/mol
  • F Fluorine × 425.74%
    18.998 × 4 = 75.992 g/mol
  • N Nitrogen × 314.23%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C14H9F4N3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C14H9F4N3?

The molar mass of C14H9F4N3 is 295.24 g/mol, calculated from standard atomic weights for 14 carbon atoms, 9 hydrogen atoms, 4 fluorine atoms and 3 nitrogen atoms. The monoisotopic mass is 295.0733 Da.

How many compounds have the formula C14H9F4N3?

CompoundList lists 10 compounds with the molecular formula C14H9F4N3, including 3-(4-Fluorophenyl)-5-methyl-7-(trifluoromethyl)pyrazolo[1,5-a]pyrimidine, 5-((3,5-Difluorophenyl)difluoromethyl)-1H-indazol-3-amine, 5-(4-Fluorophenyl)-2-methyl-7-(trifluoromethyl)pyrazolo[1,5-a]pyrimidine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H9F4N3?

C14H9F4N3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.