C14H9FO3
62 compounds have this formula on CompoundList.
- Molar mass
- 244.22g/mol
- Monoisotopic mass
- 244.0536Da
- Atoms
- 27
- Elements
- 4
- Rings plus double bonds
- 10
The formula C14H9FO3 describes a molecule made of 14 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1468.85%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 93.71%1.008 × 9 = 9.072 g/mol
- F Fluorine × 17.78%18.998 × 1 = 18.998 g/mol
- O Oxygen × 319.65%15.999 × 3 = 47.997 g/mol
Compounds with the formula C14H9FO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 62 of 62 compounds
- 5-Fluoro-2-(3-formylphenyl)benzoic acid1261970-87-9C14H9FO3
- 4-Fluoro-3-(3-formylphenyl)benzoic acid1261979-85-4C14H9FO3
- 3-Fluoro-4-(3-formylphenyl)benzoic acid1261921-36-1C14H9FO3
- 2-Fluoro-4-(3-formylphenyl)benzoic acid1261969-35-0C14H9FO3
- 5-Fluoro-2-(4-formylphenyl)benzoic acid1261993-55-8C14H9FO3
- 4-Fluoro-3-(4-formylphenyl)benzoic acid1261958-81-9C14H9FO3
- 2-Fluoro-5-(4-formylphenyl)benzoic acid1261902-69-5C14H9FO3
- 3-Formylphenyl 3-fluorobenzoate332929-51-8C14H9FO3
- 2-(3-Fluorobenzoyl)benzoic acid1580-54-7C14H9FO3
- 3-Fluoro-6-methoxy-9H-xanthen-9-one825649-99-8C14H9FO3
- 4-(4-Fluorobenzoyl)benzoic acid148038-12-4C14H9FO3
- 2-(3-Fluoro-4-formylphenyl)benzoic acid893637-60-0C14H9FO3
- 3-Formylphenyl 2-fluorobenzoate444065-24-1C14H9FO3
- 6-(4-Fluorophenyl)-1,3-benzodioxole-5-carbaldehyde927802-53-7C14H9FO3
- 7-(4-Fluorophenyl)-1,3-benzodioxole-5-carbaldehyde2241139-96-6C14H9FO3
- 7-(2-Fluorophenyl)-1,3-dioxaindane-5-carbaldehyde2241128-44-7C14H9FO3
- (3-Formylphenyl) 4-fluorobenzoate444076-31-7C14H9FO3
- 3-(3-Fluoro-4-formylphenyl)benzoic acid893637-59-7C14H9FO3
- 4-(3-Fluoro-4-formylphenyl)benzoic acid893637-57-5C14H9FO3
- 2-(4'-Fluoro-[1,1'-biphenyl]-3-yl)-2-oxoacetic acid1683546-10-2C14H9FO3
- 2-(2-Fluorobenzoyl)benzoic acid7613-47-0C14H9FO3
- Benzoic acid,2-benzoyl-6-fluoro-874113-08-3C14H9FO3
- Benzoic acid,2-benzoyl-3-fluoro-1580-53-6C14H9FO3
- 1,3-BenZodioxol-5-yl(3-fluorophenyl)methanone1332350-38-5C14H9FO3
- 4-(2-Fluoro-6-formylphenyl)benzoic acid2138342-97-7C14H9FO3
- 2-(2-Fluoro-5-formylphenyl)benzoic acid2137580-24-4C14H9FO3
- 4-(4-Fluoro-2-formylphenyl)benzoic acid2138357-39-6C14H9FO3
- 4-(3-Fluoro-2-formylphenyl)benzoic acid2137633-11-3C14H9FO3
- 2-(4-Fluoro-2-formylphenyl)benzoic acid2137816-46-5C14H9FO3
- 2-(3-Fluoro-2-formylphenyl)benzoic acid2138370-99-5C14H9FO3
- 2-(2-Fluoro-3-formylphenyl)benzoic acid2137816-17-0C14H9FO3
- 3-(2-Fluoro-5-formylphenyl)benzoic acid2137769-68-5C14H9FO3
- 3-(4-Fluoro-2-formylphenyl)benzoic acid2137823-66-4C14H9FO3
- 3-(2-Fluoro-3-formylphenyl)benzoic acid2137570-21-7C14H9FO3
- 4-(2-Fluoro-3-formylphenyl)benzoic acid2138414-82-9C14H9FO3
- 3-(3-Fluoro-2-formylphenyl)benzoic acid2138515-79-2C14H9FO3
- 3-(2-Fluoro-6-formylphenyl)benzoic acid2138255-53-3C14H9FO3
- 4-(2-Fluoro-5-formylphenyl)benzoic acid2138384-84-4C14H9FO3
Frequently asked questions
What is the molar mass of C14H9FO3?
The molar mass of C14H9FO3 is 244.22 g/mol, calculated from standard atomic weights for 14 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 3 oxygen atoms. The monoisotopic mass is 244.0536 Da.
How many compounds have the formula C14H9FO3?
CompoundList lists 62 compounds with the molecular formula C14H9FO3, including 2-(4-Fluorobenzoyl)benzoic acid, 2-Fluoro-4-(4-formylphenyl)benzoic acid, 4-Formylphenyl 4-fluorobenzoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H9FO3?
C14H9FO3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.