CompoundList
Molecular formula

C14H9N3

74 compounds have this formula on CompoundList.

Molar mass
219.25g/mol
Monoisotopic mass
219.0796Da
Atoms
26
Elements
3
Rings plus double bonds
12

The formula C14H9N3 describes a molecule made of 14 carbon atoms, 9 hydrogen atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1476.70%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 94.14%
    1.008 × 9 = 9.072 g/mol
  • N Nitrogen × 319.17%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C14H9N3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 74 of 74 compounds

Frequently asked questions

What is the molar mass of C14H9N3?

The molar mass of C14H9N3 is 219.25 g/mol, calculated from standard atomic weights for 14 carbon atoms, 9 hydrogen atoms and 3 nitrogen atoms. The monoisotopic mass is 219.0796 Da.

How many compounds have the formula C14H9N3?

CompoundList lists 74 compounds with the molecular formula C14H9N3, including 6H-Indolo(2,3-b)quinoxaline, 4-(1H-1,3-Benzodiazol-1-yl)benzonitrile, 4-(1H-1,3-Benzodiazol-2-yl)benzonitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H9N3?

C14H9N3 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.