C15H10BrF3N6O
1 compound has this formula on CompoundList.
- Molar mass
- 427.18g/mol
- Monoisotopic mass
- 426.0052Da
- Atoms
- 36
- Elements
- 6
- Rings plus double bonds
- 12
The formula C15H10BrF3N6O describes a molecule made of 15 carbon atoms, 10 hydrogen atoms, 1 bromine atom, 3 fluorine atoms, 6 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1542.18%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 102.36%1.008 × 10 = 10.080 g/mol
- Br Bromine × 118.70%79.904 × 1 = 79.904 g/mol
- F Fluorine × 313.34%18.998 × 3 = 56.994 g/mol
- N Nitrogen × 619.67%14.007 × 6 = 84.042 g/mol
- O Oxygen × 13.75%15.999 × 1 = 15.999 g/mol
Compounds with the formula C15H10BrF3N6O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C15H10BrF3N6O?
The molar mass of C15H10BrF3N6O is 427.18 g/mol, calculated from standard atomic weights for 15 carbon atoms, 10 hydrogen atoms, 1 bromine atom, 3 fluorine atoms, 6 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 426.0052 Da.
How many compounds have the formula C15H10BrF3N6O?
CompoundList lists 1 compound with the molecular formula C15H10BrF3N6O, including NS-3623. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H10BrF3N6O?
C15H10BrF3N6O has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.