CompoundList
Molecular formula

C15H14BrN3

17 compounds have this formula on CompoundList.

Molar mass
316.20g/mol
Monoisotopic mass
315.0371Da
Atoms
33
Elements
4
Rings plus double bonds
10

The formula C15H14BrN3 describes a molecule made of 15 carbon atoms, 14 hydrogen atoms, 1 bromine atom and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1556.98%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 144.46%
    1.008 × 14 = 14.112 g/mol
  • Br Bromine × 125.27%
    79.904 × 1 = 79.904 g/mol
  • N Nitrogen × 313.29%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C15H14BrN3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 17 of 17 compounds

Frequently asked questions

What is the molar mass of C15H14BrN3?

The molar mass of C15H14BrN3 is 316.20 g/mol, calculated from standard atomic weights for 15 carbon atoms, 14 hydrogen atoms, 1 bromine atom and 3 nitrogen atoms. The monoisotopic mass is 315.0371 Da.

How many compounds have the formula C15H14BrN3?

CompoundList lists 17 compounds with the molecular formula C15H14BrN3, including 4-Bromo-N-[(1-methylbenzimidazol-2-yl)methyl]aniline, N-[(4-Bromophenyl)methyl]-1-methylbenzimidazol-5-amine, [2-(4-Bromophenyl)-6-methylimidazo[1,2-a]pyridin-3-yl]methanamine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H14BrN3?

C15H14BrN3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.