C15H14ClFN2O
28 compounds have this formula on CompoundList.
- Molar mass
- 292.74g/mol
- Monoisotopic mass
- 292.0779Da
- Atoms
- 34
- Elements
- 6
- Rings plus double bonds
- 9
The formula C15H14ClFN2O describes a molecule made of 15 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 2 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1561.54%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 144.82%1.008 × 14 = 14.112 g/mol
- Cl Chlorine × 112.11%35.45 × 1 = 35.450 g/mol
- F Fluorine × 16.49%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 29.57%14.007 × 2 = 28.014 g/mol
- O Oxygen × 15.47%15.999 × 1 = 15.999 g/mol
Compounds with the formula C15H14ClFN2O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 28 of 28 compounds
- (S)-N-(2-Fluorophenyl)indoline-2-carboxamide hydrochloride3078590-95-8C15H14ClFN2O
- (S)-N-(3-Fluorophenyl)indoline-2-carboxamide hydrochloride3078592-75-0C15H14ClFN2O
- (S)-N-(4-Fluorophenyl)indoline-2-carboxamide hydrochloride3078593-47-9C15H14ClFN2O
- 3-(2-Chloro-4-fluorophenyl)-N-(pyridin-4-ylmethyl)propanamide2944480-40-2C15H14ClFN2O
Frequently asked questions
What is the molar mass of C15H14ClFN2O?
The molar mass of C15H14ClFN2O is 292.74 g/mol, calculated from standard atomic weights for 15 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 2 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 292.0779 Da.
How many compounds have the formula C15H14ClFN2O?
CompoundList lists 28 compounds with the molecular formula C15H14ClFN2O, including 1-[2-(4-Chlorophenyl)ethyl]-3-(4-fluorophenyl)urea, 2-((4-Fluorophenyl)methyl)-5-methoxy-1H-1,3-benzodiazole hydrochloride, N-(3-Chloro-2-methylphenyl)-N'-(4-fluorobenzyl)urea. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H14ClFN2O?
C15H14ClFN2O has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.