CompoundList
Molecular formula

C15H14IN3O3

4 compounds have this formula on CompoundList.

Molar mass
411.20g/mol
Monoisotopic mass
411.0080Da
Atoms
36
Elements
5
Rings plus double bonds
10

The formula C15H14IN3O3 describes a molecule made of 15 carbon atoms, 14 hydrogen atoms, 1 iodine atom, 3 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1543.81%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 143.43%
    1.008 × 14 = 14.112 g/mol
  • I Iodine × 130.86%
    126.9 × 1 = 126.900 g/mol
  • N Nitrogen × 310.22%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 311.67%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C15H14IN3O3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C15H14IN3O3?

The molar mass of C15H14IN3O3 is 411.20 g/mol, calculated from standard atomic weights for 15 carbon atoms, 14 hydrogen atoms, 1 iodine atom, 3 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 411.0080 Da.

How many compounds have the formula C15H14IN3O3?

CompoundList lists 4 compounds with the molecular formula C15H14IN3O3, including Iomazenil (123I), Iomazenil, 8-Iodo-5-methyl-6-oxo-5,6-dihydro-4H-imidazo[1,5-a][1,4]benzodiazepine-3-carboxylic acid ethyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H14IN3O3?

C15H14IN3O3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.