C15H21BrIN
1 compound has this formula on CompoundList.
- Molar mass
- 422.14g/mol
- Monoisotopic mass
- 420.9902Da
- Atoms
- 39
- Elements
- 5
- Rings plus double bonds
- 5
The formula C15H21BrIN describes a molecule made of 15 carbon atoms, 21 hydrogen atoms, 1 bromine atom, 1 iodine atom and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1542.68%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 215.01%1.008 × 21 = 21.168 g/mol
- Br Bromine × 118.93%79.904 × 1 = 79.904 g/mol
- I Iodine × 130.06%126.9 × 1 = 126.900 g/mol
- N Nitrogen × 13.32%14.007 × 1 = 14.007 g/mol
Compounds with the formula C15H21BrIN
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C15H21BrIN?
The molar mass of C15H21BrIN is 422.14 g/mol, calculated from standard atomic weights for 15 carbon atoms, 21 hydrogen atoms, 1 bromine atom, 1 iodine atom and 1 nitrogen atom. The monoisotopic mass is 420.9902 Da.
How many compounds have the formula C15H21BrIN?
CompoundList lists 1 compound with the molecular formula C15H21BrIN, including 5-Bromo-1-butyl-2,3,3-trimethyl-3H-indol-1-ium iodide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H21BrIN?
C15H21BrIN has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.