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Molecular formula

C15H22Cl3N3O

3 compounds have this formula on CompoundList.

Molar mass
366.71g/mol
Monoisotopic mass
365.0828Da
Atoms
44
Elements
5
Rings plus double bonds
5

The formula C15H22Cl3N3O describes a molecule made of 15 carbon atoms, 22 hydrogen atoms, 3 chlorine atoms, 3 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1549.13%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 226.05%
    1.008 × 22 = 22.176 g/mol
  • Cl Chlorine × 329.00%
    35.45 × 3 = 106.350 g/mol
  • N Nitrogen × 311.46%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 14.36%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C15H22Cl3N3O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

2-Chloro-4-({[4-(methoxymethyl)piperidin-4-yl]methyl}amino)benzonitrile dihydrochloride chemical structure, C15H22Cl3N3O, CAS 2639403-71-5
2-Chloro-4-({[4-(methoxymethyl)piperidin-4-yl]methyl}amino)benzonitrile dihydrochloride
CAS 2639403-71-5C15H22Cl3N3O
1,3-Propanediamine, N-(2-chloroethyl)-N'-(6-methoxy-4-quinolinyl)-, dihydrochloride chemical structure, C15H22Cl3N3O, CAS 38925-90-5
1,3-Propanediamine, N-(2-chloroethyl)-N'-(6-methoxy-4-quinolinyl)-, dihydrochloride
CAS 38925-90-5C15H22Cl3N3O
3-Amino-6-[N,N-bis(3-chloropropyl)amino]-1,2,3,4-tetrahydro-2-oxo-quinoline Hydrochloride chemical structure, C15H22Cl3N3O, CAS 2509093-29-0
3-Amino-6-[N,N-bis(3-chloropropyl)amino]-1,2,3,4-tetrahydro-2-oxo-quinoline Hydrochloride
CAS 2509093-29-0C15H22Cl3N3O

Frequently asked questions

What is the molar mass of C15H22Cl3N3O?

The molar mass of C15H22Cl3N3O is 366.71 g/mol, calculated from standard atomic weights for 15 carbon atoms, 22 hydrogen atoms, 3 chlorine atoms, 3 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 365.0828 Da.

How many compounds have the formula C15H22Cl3N3O?

CompoundList lists 3 compounds with the molecular formula C15H22Cl3N3O, including 2-Chloro-4-({[4-(methoxymethyl)piperidin-4-yl]methyl}amino)benzonitrile dihydrochloride, 1,3-Propanediamine, N-(2-chloroethyl)-N'-(6-methoxy-4-quinolinyl)-, dihydrochloride, 3-Amino-6-[N,N-bis(3-chloropropyl)amino]-1,2,3,4-tetrahydro-2-oxo-quinoline Hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H22Cl3N3O?

C15H22Cl3N3O has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.