CompoundList
Molecular formula

C15H23N3O10

7 compounds have this formula on CompoundList.

Molar mass
405.36g/mol
Monoisotopic mass
405.1383Da
Atoms
51
Elements
4
Rings plus double bonds
6

The formula C15H23N3O10 describes a molecule made of 15 carbon atoms, 23 hydrogen atoms, 3 nitrogen atoms and 10 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1544.45%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 235.72%
    1.008 × 23 = 23.184 g/mol
  • N Nitrogen × 310.37%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 1039.47%
    15.999 × 10 = 159.990 g/mol
Look up another formula

Compounds with the formula C15H23N3O10

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C15H23N3O10?

The molar mass of C15H23N3O10 is 405.36 g/mol, calculated from standard atomic weights for 15 carbon atoms, 23 hydrogen atoms, 3 nitrogen atoms and 10 oxygen atoms. The monoisotopic mass is 405.1383 Da.

How many compounds have the formula C15H23N3O10?

CompoundList lists 7 compounds with the molecular formula C15H23N3O10, including Glu-Glu-Glu, 3'-O-Galactopyranosylcytarabine, H-Glu(Glu(Glu-OH)-OH)-OH. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H23N3O10?

C15H23N3O10 has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.