CompoundList
Molecular formula

C15H26N4O5

10 compounds have this formula on CompoundList.

Molar mass
342.40g/mol
Monoisotopic mass
342.1903Da
Atoms
50
Elements
4
Rings plus double bonds
5

The formula C15H26N4O5 describes a molecule made of 15 carbon atoms, 26 hydrogen atoms, 4 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1552.62%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 267.65%
    1.008 × 26 = 26.208 g/mol
  • N Nitrogen × 416.36%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 523.36%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C15H26N4O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C15H26N4O5?

The molar mass of C15H26N4O5 is 342.40 g/mol, calculated from standard atomic weights for 15 carbon atoms, 26 hydrogen atoms, 4 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 342.1903 Da.

How many compounds have the formula C15H26N4O5?

CompoundList lists 10 compounds with the molecular formula C15H26N4O5, including Valyl-alanyl-prolyl-glycine, Glidobactamine, {2-[5-(tert-Butoxycarbonylaminomethyl)-[1,3,4]oxadiazol-2-yl]-ethyl}-carbamic acid tert-butyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H26N4O5?

C15H26N4O5 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.