CompoundList
Molecular formula

C15H9BrN4S

8 compounds have this formula on CompoundList.

Molar mass
357.23g/mol
Monoisotopic mass
355.9731Da
Atoms
30
Elements
5
Rings plus double bonds
13

The formula C15H9BrN4S describes a molecule made of 15 carbon atoms, 9 hydrogen atoms, 1 bromine atom, 4 nitrogen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1550.43%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 92.54%
    1.008 × 9 = 9.072 g/mol
  • Br Bromine × 122.37%
    79.904 × 1 = 79.904 g/mol
  • N Nitrogen × 415.68%
    14.007 × 4 = 56.028 g/mol
  • S Sulfur × 18.97%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C15H9BrN4S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 8 of 8 compounds

Frequently asked questions

What is the molar mass of C15H9BrN4S?

The molar mass of C15H9BrN4S is 357.23 g/mol, calculated from standard atomic weights for 15 carbon atoms, 9 hydrogen atoms, 1 bromine atom, 4 nitrogen atoms and 1 sulfur atom. The monoisotopic mass is 355.9731 Da.

How many compounds have the formula C15H9BrN4S?

CompoundList lists 8 compounds with the molecular formula C15H9BrN4S, including 2-(2-Bromophenyl)[1,2,4]triazolo[1,5-c]quinazoline-5-thiol, Thiazolo[5,4-g]quinazolin-8-amine, N-(3-bromophenyl)-, 3-(2-Bromophenyl)-6-phenyl[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H9BrN4S?

C15H9BrN4S has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.