CompoundList
Molecular formula

C15H9FO4

9 compounds have this formula on CompoundList.

Molar mass
272.23g/mol
Monoisotopic mass
272.0485Da
Atoms
29
Elements
4
Rings plus double bonds
11

The formula C15H9FO4 describes a molecule made of 15 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1566.18%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 93.33%
    1.008 × 9 = 9.072 g/mol
  • F Fluorine × 16.98%
    18.998 × 1 = 18.998 g/mol
  • O Oxygen × 423.51%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C15H9FO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C15H9FO4?

The molar mass of C15H9FO4 is 272.23 g/mol, calculated from standard atomic weights for 15 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 4 oxygen atoms. The monoisotopic mass is 272.0485 Da.

How many compounds have the formula C15H9FO4?

CompoundList lists 9 compounds with the molecular formula C15H9FO4, including 2-(4-Fluorophenyl)-5,7-dihydroxy-4H-1-benzopyran-4-one, 4H-1-Benzopyran-4-one, 3-(2-fluorophenoxy)-7-hydroxy-, 4H-1-Benzopyran-4-one, 3-(4-fluorophenoxy)-7-hydroxy-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H9FO4?

C15H9FO4 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.