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Molecular formula

C16H11N7S

4 compounds have this formula on CompoundList.

Molar mass
333.37g/mol
Monoisotopic mass
333.0797Da
Atoms
35
Elements
4
Rings plus double bonds
15

The formula C16H11N7S describes a molecule made of 16 carbon atoms, 11 hydrogen atoms, 7 nitrogen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1657.65%
    12.011 × 16 = 192.176 g/mol
  • H Hydrogen × 113.33%
    1.008 × 11 = 11.088 g/mol
  • N Nitrogen × 729.41%
    14.007 × 7 = 98.049 g/mol
  • S Sulfur × 19.62%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C16H11N7S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

3-(1-Benzotriazolylmethyl)-6-phenyl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole chemical structure, C16H11N7S, CAS 122503-13-3
3-(1-Benzotriazolylmethyl)-6-phenyl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole
CAS 122503-13-3C16H11N7S
3-(Benzimidazol-1-ylmethyl)-6-pyridin-3-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole chemical structure, C16H11N7S, CAS 791806-13-8
3-(Benzimidazol-1-ylmethyl)-6-pyridin-3-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole
CAS 791806-13-8C16H11N7S
3-(Benzimidazol-1-ylmethyl)-6-pyridin-4-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole chemical structure, C16H11N7S, CAS 825605-21-8
3-(Benzimidazol-1-ylmethyl)-6-pyridin-4-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole
CAS 825605-21-8C16H11N7S
3-(Benzimidazol-1-ylmethyl)-6-pyridin-2-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole chemical structure, C16H11N7S, CAS 791806-12-7
3-(Benzimidazol-1-ylmethyl)-6-pyridin-2-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole
CAS 791806-12-7C16H11N7S

Frequently asked questions

What is the molar mass of C16H11N7S?

The molar mass of C16H11N7S is 333.37 g/mol, calculated from standard atomic weights for 16 carbon atoms, 11 hydrogen atoms, 7 nitrogen atoms and 1 sulfur atom. The monoisotopic mass is 333.0797 Da.

How many compounds have the formula C16H11N7S?

CompoundList lists 4 compounds with the molecular formula C16H11N7S, including 3-(1-Benzotriazolylmethyl)-6-phenyl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole, 3-(Benzimidazol-1-ylmethyl)-6-pyridin-3-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole, 3-(Benzimidazol-1-ylmethyl)-6-pyridin-4-yl-[1,2,4]triazolo[3,4-b][1,3,4]thiadiazole. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C16H11N7S?

C16H11N7S has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.