C16H14FN3O3
34 compounds have this formula on CompoundList.
- Molar mass
- 315.30g/mol
- Monoisotopic mass
- 315.1019Da
- Atoms
- 37
- Elements
- 5
- Rings plus double bonds
- 11
The formula C16H14FN3O3 describes a molecule made of 16 carbon atoms, 14 hydrogen atoms, 1 fluorine atom, 3 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1660.95%12.011 × 16 = 192.176 g/mol
- H Hydrogen × 144.48%1.008 × 14 = 14.112 g/mol
- F Fluorine × 16.03%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 313.33%14.007 × 3 = 42.021 g/mol
- O Oxygen × 315.22%15.999 × 3 = 47.997 g/mol
Compounds with the formula C16H14FN3O3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 34 of 34 compounds
- 1-[(2-Fluorophenyl)methyl]-5-(3-isoxazolyl)-1H-pyrazole-3-carboxylic acid ethyl ester1354044-05-5C16H14FN3O3
- 2-[2-Fluoro-6-(3-nitrophenoxy)phenyl]-1,4,5,6-tetrahydropyrimidine1267462-39-4C16H14FN3O3
- 5-(4-((2-Fluorobenzyl)oxy)-3-methoxyphenyl)-1,3,4-oxadiazol-2-amine1706463-93-5C16H14FN3O3
- 3-Cyclopropyl-N-[1-(4-fluorophenyl)-2-oxoazetidin-3-yl]-1,2-oxazole-4-carboxamide2223722-23-2C16H14FN3O3
- 4-Cyclopropyl-N-[1-(4-fluorophenyl)-2-oxoazetidin-3-yl]-1,3-oxazole-5-carboxamide2223729-78-8C16H14FN3O3
- 2-[(2E)-2-(3-Fluorobenzylidene)hydrazino]-N-(3-methoxyphenyl)-2-oxoacetamide769144-00-5C16H14FN3O3
- Methyl 3-[2-(4-fluorophenyl)-4-oxo-4H,5H-pyrazolo[1,5-a]pyrazin-5-yl]propanoate2415500-26-2C16H14FN3O3
- 5-(4-Fluorophenoxy)-1,3,6-trimethyl-1H,2H,3H,4H-pyrido[2,3-d]pyrimidine-2,4-dione3054583-09-1C16H14FN3O3
- 4-(3-((2-Fluorophenoxy)methyl)-1H-1,2,4-triazol-5-yl)-2-methoxyphenol1416348-43-0C16H14FN3O3
- 4-(3-((3-Fluorophenoxy)methyl)-1H-1,2,4-triazol-5-yl)-2-methoxyphenol1416345-22-6C16H14FN3O3
Frequently asked questions
What is the molar mass of C16H14FN3O3?
The molar mass of C16H14FN3O3 is 315.30 g/mol, calculated from standard atomic weights for 16 carbon atoms, 14 hydrogen atoms, 1 fluorine atom, 3 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 315.1019 Da.
How many compounds have the formula C16H14FN3O3?
CompoundList lists 34 compounds with the molecular formula C16H14FN3O3, including (5-Fluoro-2-hydroxyphenyl)-[1-(2-hydroxyethyl)-3-methylpyrazolo[3,4-b]pyridin-5-yl]methanone, 3-[(3-Fluorophenyl)methyl]-5-methoxy-1-methylpyrido[2,3-d]pyrimidine-2,4-dione, 3-[(4-Fluorophenyl)methyl]-5-methoxy-1-methylpyrido[2,3-d]pyrimidine-2,4-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C16H14FN3O3?
C16H14FN3O3 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.