CompoundList
Molecular formula

C16H31BrO

6 compounds have this formula on CompoundList.

Molar mass
319.33g/mol
Monoisotopic mass
318.1558Da
Atoms
49
Elements
4
Rings plus double bonds
1

The formula C16H31BrO describes a molecule made of 16 carbon atoms, 31 hydrogen atoms, 1 bromine atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1660.18%
    12.011 × 16 = 192.176 g/mol
  • H Hydrogen × 319.79%
    1.008 × 31 = 31.248 g/mol
  • Br Bromine × 125.02%
    79.904 × 1 = 79.904 g/mol
  • O Oxygen × 15.01%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C16H31BrO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 6 of 6 compounds

Frequently asked questions

What is the molar mass of C16H31BrO?

The molar mass of C16H31BrO is 319.33 g/mol, calculated from standard atomic weights for 16 carbon atoms, 31 hydrogen atoms, 1 bromine atom and 1 oxygen atom. The monoisotopic mass is 318.1558 Da.

How many compounds have the formula C16H31BrO?

CompoundList lists 6 compounds with the molecular formula C16H31BrO, including 1-Bromohexadecan-2-one, Hexadecanoyl bromide, 16-Bromohexadecanal. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C16H31BrO?

C16H31BrO has a degree of unsaturation of 1. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.