CompoundList
Molecular formula

C16H31N3O4

12 compounds have this formula on CompoundList.

Molar mass
329.44g/mol
Monoisotopic mass
329.2315Da
Atoms
54
Elements
4
Rings plus double bonds
3

The formula C16H31N3O4 describes a molecule made of 16 carbon atoms, 31 hydrogen atoms, 3 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1658.33%
    12.011 × 16 = 192.176 g/mol
  • H Hydrogen × 319.49%
    1.008 × 31 = 31.248 g/mol
  • N Nitrogen × 312.76%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 419.43%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C16H31N3O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 12 of 12 compounds

Frequently asked questions

What is the molar mass of C16H31N3O4?

The molar mass of C16H31N3O4 is 329.44 g/mol, calculated from standard atomic weights for 16 carbon atoms, 31 hydrogen atoms, 3 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 329.2315 Da.

How many compounds have the formula C16H31N3O4?

CompoundList lists 12 compounds with the molecular formula C16H31N3O4, including BB 3497, Leu-Val-Val, L-Valyl-L-valyl-L-isoleucine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C16H31N3O4?

C16H31N3O4 has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.