C17H14Br4O
2 compounds have this formula on CompoundList.
- Molar mass
- 553.91g/mol
- Monoisotopic mass
- 549.7778Da
- Atoms
- 36
- Elements
- 4
- Rings plus double bonds
- 9
The formula C17H14Br4O describes a molecule made of 17 carbon atoms, 14 hydrogen atoms, 4 bromine atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1736.86%12.011 × 17 = 204.187 g/mol
- H Hydrogen × 142.55%1.008 × 14 = 14.112 g/mol
- Br Bromine × 457.70%79.904 × 4 = 319.616 g/mol
- O Oxygen × 12.89%15.999 × 1 = 15.999 g/mol
Compounds with the formula C17H14Br4O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C17H14Br4O?
The molar mass of C17H14Br4O is 553.91 g/mol, calculated from standard atomic weights for 17 carbon atoms, 14 hydrogen atoms, 4 bromine atoms and 1 oxygen atom. The monoisotopic mass is 549.7778 Da.
How many compounds have the formula C17H14Br4O?
CompoundList lists 2 compounds with the molecular formula C17H14Br4O, including 1,5-Diphenyl-1,2,4,5-tetrabromo-3-pentanone, 1-Pentanone, 2,3,4,5-tetrabromo-1,5-diphenyl-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C17H14Br4O?
C17H14Br4O has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.