CompoundList
Molecular formula

C17H14F2N8

1 compound has this formula on CompoundList.

Molar mass
368.35g/mol
Monoisotopic mass
368.1309Da
Atoms
41
Elements
4
Rings plus double bonds
14

The formula C17H14F2N8 describes a molecule made of 17 carbon atoms, 14 hydrogen atoms, 2 fluorine atoms and 8 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1755.43%
    12.011 × 17 = 204.187 g/mol
  • H Hydrogen × 143.83%
    1.008 × 14 = 14.112 g/mol
  • F Fluorine × 210.32%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 830.42%
    14.007 × 8 = 112.056 g/mol
Look up another formula

Compounds with the formula C17H14F2N8

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C17H14F2N8?

The molar mass of C17H14F2N8 is 368.35 g/mol, calculated from standard atomic weights for 17 carbon atoms, 14 hydrogen atoms, 2 fluorine atoms and 8 nitrogen atoms. The monoisotopic mass is 368.1309 Da.

How many compounds have the formula C17H14F2N8?

CompoundList lists 1 compound with the molecular formula C17H14F2N8, including 2-[5-Fluoro-1-(2-fluorobenzyl)-1H-pyrazolo[3,4-b]pyridin-3-yl]pyrimidine-4,5,6-triamine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C17H14F2N8?

C17H14F2N8 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.