CompoundList
Molecular formula

C17H15BrO5

13 compounds have this formula on CompoundList.

Molar mass
379.21g/mol
Monoisotopic mass
378.0103Da
Atoms
38
Elements
4
Rings plus double bonds
10

The formula C17H15BrO5 describes a molecule made of 17 carbon atoms, 15 hydrogen atoms, 1 bromine atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1753.85%
    12.011 × 17 = 204.187 g/mol
  • H Hydrogen × 153.99%
    1.008 × 15 = 15.120 g/mol
  • Br Bromine × 121.07%
    79.904 × 1 = 79.904 g/mol
  • O Oxygen × 521.10%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C17H15BrO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 13 of 13 compounds

Frequently asked questions

What is the molar mass of C17H15BrO5?

The molar mass of C17H15BrO5 is 379.21 g/mol, calculated from standard atomic weights for 17 carbon atoms, 15 hydrogen atoms, 1 bromine atom and 5 oxygen atoms. The monoisotopic mass is 378.0103 Da.

How many compounds have the formula C17H15BrO5?

CompoundList lists 13 compounds with the molecular formula C17H15BrO5, including 3-((2-Bromo-6-ethoxy-4-formylphenoxy)methyl)benzoic acid, 4-[(2-Bromo-6-ethoxy-4-formylphenoxy)methyl]benzoic acid, 2-(4-Bromophenyl)-2-oxoethyl 3,4-dimethoxybenzoate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C17H15BrO5?

C17H15BrO5 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.